What will be the pH and Normality when 33.6 liters of HCL having 1.18 s.g.and 36% concentration
To determine the pH and normality of the HCl solution, we will follow a step-by-step process using the given information:
Step 1: Calculate the molarity of the HCl solution.
Molarity (M) = (Concentration * Density * 1000) / (36.461 g/mol)
Given: Concentration = 36%, Density = 1.18 g/mL
Molarity (M) = (36 * 1.18 * 1000) / (36.461)
Step 2: Calculate the normality of the HCl solution.
Normality (N) = Molarity * Basicity
Basicity of HCl is 1, as it donates 1 H+ ion.
Normality (N) = Molarity * 1
Step 3: Calculate the pH of the HCl solution using the H+ concentration.
pH = -log[H+]
[H+] concentration is equal to the molarity of the HCl solution.
Now, let's calculate the values:
Step 1: Calculate the molarity of the HCl solution.
Molarity (M) = (36 * 1.18 * 1000) / (36.461)
Molarity (M) = 1.191 M
Step 2: Calculate the normality of the HCl solution.
Normality (N) = Molarity * Basicity
Normality (N) = 1.191 * 1
Normality (N) = 1.191 N
Step 3: Calculate the pH of the HCl solution.
pH = -log[H+]
[H+] concentration is equal to the molarity of the HCl solution.
pH = -log(1.191)
pH ≈ -0.075
Therefore, the pH of the HCl solution is approximately -0.075, and the normality is 1.191 N.