math forms for construction are made of cement like the one shown. this one has a hollow cylindrical center. what is the total volume of the form? use 3.14 as an approximation for pi. round answer to nearest tenth.
Diameter for cylinder is 0.5 ft
Width for cube is 1 ft
Length for cube is 1.5 ft
Height is unknown but a lone crosses diagonally across the cube which is 2 ft
just plug the numbers into your volume formulas.
The square-ish part cannot be a cube, since the sides differ in length. Must be a rectangular prism.
You don't say which side has the diagonal line, but using the Pythagorean theorem to find h,
if it is on the 1" side, then
1^2 + h^2 = 2^2
If it is on the 1.5" side, then
1.5^2 + h^2 = 2^2
Now take a stab at it.
No the front side has the diagonal side and it is 2 ft and thank u
no problem.
Of course, telling me the front side has the line does not help, since I cannot see which face is the front.
How would u find the area of base for the cylinder, how would u find the volume of cylinder
Diameter is 0.5
???
Where should I use pi in here, I don't get it can u please show me how to do it
the area of the base with diameter d is
π/4 d^2 = π/4 * .5^2 = π/16
the volume is just base * height
better review your formulas. Here's a good reference:
http://www.regentsprep.org/regents/math/algebra/as2/solids.htm
if you still have questions, or just want to explore, remember that google is your friend.
wikipedia also has a good table with lots of solids and their properties.
For the answer of the cylinder I got
V=2.0724 ft
Then added them together
2.0724+1.98= 4.054ft
Is that the right answer
Can you also help me with another one, it has a cone on top of a cylinder
The cones slant height is 6in
The cones length(radius) is 4 in
The cones height is not known
The cylinders height is 7 in
The cylinders length(radius) is also 4 in
The radius is half of the cylinder, cone
I don't know what to do, I need to find the total volume of the model
for the cone, the slant height s and the height h and the radius r obey
s^2 = r^2+h^2
so, the height is √20=2√5
cone volume is 1/3 πr^2h = 32√5 π/3
cylinder volume is πr^2h = 102π
so add them up
To find the total volume of the form, we need to calculate the volumes of both the hollow cylindrical center and the cube separately, and then add them together.
Let's start with the cylindrical center:
The diameter is given as 0.5 ft, which means the radius is half of that, so the radius (r) of the cylinder is 0.5/2 = 0.25 ft.
To find the volume of a cylinder, we use the formula:
Volume of a cylinder = π * r^2 * h,
where π is the approximation for pi, r is the radius, and h is the height.
However, in this case, the height is not given directly. But we know that a line crosses diagonally across the cube, which has a length of 1.5 ft, width of 1 ft, and a height of 2 ft.
Using the Pythagorean theorem, we can find the height of the cylindrical center. The diagonal (d) is the hypotenuse of a right triangle, with the length and width as the other two sides. So:
d^2 = length^2 + width^2
d^2 = 1.5^2 + 1^2
d^2 = 2.25 + 1
d^2 = 3.25
d ≈ √(3.25)
d ≈ 1.8 ft
Therefore, the height of the cylindrical center is approximately 1.8 ft.
Now we can calculate the volume of the cylindrical center:
Volume of cylindrical center = π * r^2 * h
Volume of cylindrical center = 3.14 * (0.25)^2 * 1.8
Volume of cylindrical center ≈ 0.3534 ft^3 (rounded to four decimal places)
Next, let's find the volume of the cube:
Volume of a cube = length * width * height
Volume of cube = 1.5 ft * 1 ft * 2 ft
Volume of cube = 3 ft^3
Now, we add the volumes of the cylindrical center and the cube together to get the total volume of the form:
Total volume = volume of cylindrical center + volume of cube
Total volume ≈ 0.3534 ft^3 + 3 ft^3
Total volume ≈ 3.3534 ft^3 (rounded to four decimal places)
Therefore, the total volume of the form, rounded to the nearest tenth, is approximately 3.4 ft^3.