out of 10 litre a milkman sells some milk at the rate of Rs 15 perlitre and some at the rate of 12 per litre . He gets Rs 141 on selling it. Find the quantity of milk he sold at each rate.

Milk sold at rate of 15rs = x

Milk sold at rate of 12 rs = y
Equation @ =
X + y = 10
:equation 2
15x + 12y = 141
Multi @ by 12 then getting
12x + 12y =120 -----------------3
: subtracting 3 from 2
15x + 12y = 141
_ 12x + 12y =120
---------------------------
3x = 21
:x = 7
When x

Milk sold at rate of 15rs = x

Milk sold at rate of 12 rs = y
Equation @ =
X + y = 10
:equation 2
15x + 12y = 141
Multi @ by 12 then getting
12x + 12y =120 -----------------3
: subtracting 3 from 2
15x + 12y = 141
_ 12x + 12y =120
---------------------------
3x = 21
:x = 7
When x = 7 in equation @
7 + y = 10
: y = 10 - 7
: y = 3

15x + 12(10-x) = 141

solve for x to get the amount sold at 15

how to do pls help me but see that it is a ssc sum

Milk sold at a rate 15rs=x

Milk sold at a rate of 12rs =y
Equatoin
=x+y=10
Equation 2
15x+12y=141

15x + 120 - 12x = 141

15x - 12x = 141 - 120
3x = 21
x = 21/3
x = 7
is it right but it is told of 10litres

Explain properly k

you have found x. But how does that help you answer the question asked?