On the semi - reactions below is correct to say:
Li + + 1℮- => Li. Eº = -3,04V.
Au 3+ + 3℮- => Au. Eº = + 1,50V.
Pb 2+ + 2℮- => Pb . Eº = - 0,13V.
Ag + + 1℮- => Ag. Eº = + 0,80V.
a) In the semi reaction Ag, the potential fold if the number of moles of Ag fold.
b)all the half reactions, expression oxidation potentials of all the elements shown.
c)The lithium reduction potential is greatest among all tariff elements above.
d) In a reaction between Li + and Pb2 + lithium is reduced.
e)none of the alternatives
Frankly I don't understand the question. What is a potential fold?
To determine the correctness of each statement, let's analyze each one individually:
a) In the semi-reaction Ag, the potential folds if the number of moles of Ag fold.
To determine if the potential folds when the number of moles of Ag folds, we need to understand the relationship between the number of moles and the potential. Generally, in a redox reaction, the potential is independent of the stoichiometry (number of moles) of the species involved. So, the statement is incorrect.
b) All the half reactions, express oxidation potentials of all the elements shown.
To express the oxidation potentials of the half reactions, we need to reverse the reduction potentials given. The oxidation potential is the negative of the reduction potential for a given redox reaction. So, the statement is correct.
The oxidation potentials are as follows:
- Li -> Li+ + e-: Eº = +3.04V
- Au3+ + 3e- -> Au: Eº = -1.50V
- Pb2+ + 2e- -> Pb: Eº = +0.13V
- Ag+ + e- -> Ag: Eº = -0.80V
c) The lithium reduction potential is greatest among all the elements above.
The reduction potential indicates the tendency of a species to gain electrons and be reduced. Comparing the reduction potentials given, we can see that the highest reduction potential is +3.04V for Li+ + e- to form Li. Therefore, the statement is correct.
d) In a reaction between Li+ and Pb2+, lithium is reduced.
To determine if lithium is reduced in a reaction between Li+ and Pb2+, we compare their reduction potentials. The reduction potential for Li+ + e- to form Li is +3.04V, while the reduction potential for Pb2+ + 2e- to form Pb is +0.13V. Since the reduction potential for Li+ is greater than that of Pb2+, lithium is preferentially reduced. Therefore, the statement is correct.
e) None of the alternatives.
Based on the analysis of the previous statements, the correct statement is d) In a reaction between Li+ and Pb2+, lithium is reduced.