For an ocean wave that has the crests 6 m apart and passing a boat every two seconds, calculate the speed of the wave.
I guess the boat is anchored?
6 m/2 s = 3 m/s
Note:
That is the speed of the crest or "phase velocity". The speed of the group of waves, the "group velocity" is (1/2) of that if they are deep water waves. Energy is propagated at the group velocity. In real life the front wave is constantly disappearing and being replaced by one behind it.
http://oceanworld.tamu.edu/resources/ocng_textbook/chapter16/chapter16_01.htm
A human ear can hear as low as 15.6 Hz. If the speed of sound in the air was measured to be 340.5 m/s, calculate the wavelength of this wave.
To calculate the speed of the wave, we need to know the distance between the crests and the time it takes for the wave to pass a specific point (in this case, a boat).
Given:
- Distance between the crests (wavelength) = 6 m
- Time taken for the wave to pass the boat (period) = 2 seconds
To find the speed of the wave, we'll use the formula:
Speed (v) = Wavelength (λ) / Period (T)
Plugging in the values we have:
Speed (v) = 6 m / 2 seconds = 3 m/s
Therefore, the speed of the wave is 3 m/s.