8th grade homework: 3 digits, divisible by 5, odd number, product of the digits is 15, sum of the digits is less than 10 and it less than 12 by 12.
ends in 5 or 0
odd, so ends in 5
100 a + 10 b + c
We know c = 5
100 a + 10 b + 5
a b 5 = 15
or a b = 3
a + b <5
100a + 10 b < 144
so a = 1
since a b = 3, b = 3
so
135