The sum of three numbers equal 92.
The second number is 8 more than the first number.
The third number is 2 times the second number.
What is the first number?
Thank you.
Let's assume the first number is 'x'.
According to the information given, the second number is 8 more than the first number. Therefore, the second number is 'x + 8'.
The third number is 2 times the second number. Therefore, the third number is 2 * (x + 8), which can be simplified as '2x + 16'.
The sum of the three numbers is 92. So, we can write the equation as:
x + (x + 8) + (2x + 16) = 92
Now, let's solve the equation step-by-step to find the value of 'x'.
Combining like terms, we get:
4x + 24 = 92
Subtracting 24 from both sides, we get:
4x = 68
Dividing both sides by 4, we get:
x = 17
Therefore, the first number is 17.
To find the first number, let's set up equations based on the given information.
Let's assume the first number is "x".
According to the given information:
- The second number is "8 more than the first number", so the second number is x + 8.
- The third number is "2 times the second number", so the third number is 2(x + 8), which simplifies to 2x + 16.
Now, we know that the sum of these three numbers is 92. Therefore, we can set up the following equation:
x + (x + 8) + (2x + 16) = 92
To solve this equation, let's combine like terms:
4x + 24 = 92
Now, let's isolate x by subtracting 24 from both sides of the equation:
4x = 92 - 24
4x = 68
Finally, divide both sides of the equation by 4 to solve for x:
x = 68 / 4
x = 17
Hence, the first number is 17.
1st --- x
2nd --- x+8
3rd ----2(x+8)
solve for x
x + x+8 + 2(x+8) = 92