The perimeter of a rectangle is 154 feet. The length of the rectangle is 55 feet. What is the width of the rectangle?
2 w + 2 L = 154
L = 55
so
2 w + 110 = 154
2 w = 44
w = 22
The perimeter of a rectangular jewelry store is 154 feet. It is 44 feet long. How wide is it?
To find the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is:
Perimeter = 2(length + width)
Given that the perimeter of the rectangle is 154 feet and the length is 55 feet, we can substitute these values into the formula:
154 = 2(55 + width)
Now, we can solve for the width:
154 = 2(55 + width)
154 = 110 + 2*width
Subtract 110 from both sides:
154 - 110 = 2*width
44 = 2*width
Divide both sides by 2 to isolate the width:
44/2 = width
22 = width
Therefore, the width of the rectangle is 22 feet.
To find the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is given by P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
In this case, we are given the perimeter (P) as 154 feet and the length (L) as 55 feet. We can substitute these values into the formula:
154 = 2(55) + 2W
To solve for W, we can simplify the equation:
154 = 110 + 2W
Subtracting 110 from both sides of the equation, we get:
44 = 2W
Dividing both sides of the equation by 2, we can isolate W:
44/2 = 2W/2
22 = W
Therefore, the width of the rectangle is 22 feet.