What is the net force acting on the object below?

Its a square and on the left side it has to 5's pointing to the square.

A. 0 N
B. 5 N
C. 10 N
D. 25 N

Not sure?

Yes sorry and you just add right

If the forces are in the same direction they add, yes

Thanks

To determine the net force acting on the object, you need to calculate the sum of all the individual forces acting on it. In this case, you mentioned there are two forces pointing to the square, both with a magnitude of 5 N each. Since the forces are in the same direction, you can find the net force by simply adding their magnitudes:

Net Force = Force 1 + Force 2
= 5 N + 5 N
= 10 N

Therefore, the net force acting on the object is 10 N.

The correct answer is C. 10 N.

assuming you mean two 5's, then they add up, making 10N.