Two point charges experience an attractive force of 5N when they are separated by 1m.what force do they experience when their separation is 2m? What is the value of the charges
Using coluomb's law
F=KQ1Q2/r^2
5=8.99*10^9*Q1*Q2/1
force inversely proportional to distance squared
(1/4)5
You can only do the second part if you know that the charges are equal.
then as you pointed out
Q^2 = 5/k
Pls be mathematical
I can not be more mathematical than to say if you double the distance you divide the force by 4
2^2 = 4
To find the force experienced by the two point charges when their separation is 2m, we can use Coulomb's law.
Coulomb's law states that the force (F) between two point charges is directly proportional to the product of their charges (Q1 and Q2) and inversely proportional to the square of the distance between them (r).
The formula is:
F = k * (Q1 * Q2) / r^2
Given that the force (F) between the two charges when their separation is 1m is 5N, we can substitute these values into the formula:
5 = (8.99 * 10^9) * (Q1 * Q2) / 1^2
Now, to find the force when their separation is 2m, we need to calculate the charges Q1 and Q2. Since we don't have the individual values of the charges, we will assign variables to them, such as Q1 = x and Q2 = y.
So, the equation becomes:
5 = (8.99 * 10^9) * (x * y) / 1^2
To make things simpler, we can multiply both sides of the equation by 1^2, which results in:
5 = (8.99 * 10^9) * (x * y)
Now, with the new equation, we can calculate the values of Q1 and Q2 by manipulating the equation. However, without additional information or constraints, we cannot determine their exact values.
But if you have specific values for Q1 or Q2, you can substitute them into the equation to find the other charge.