what must the value(s) of k be so that 2xsq +(k-3)x+k-5=0 has one real root ? Two real roots? no real root?
If 2x^2 + (k-3)x + k-5 = 0 has only one real root, then the discriminant b^2 - 4ac = 0
(k-3)^2 - 4(2)(k-5) = 0
k^2 - 6k + 9 - 8k + 40 = 0
k^2 - 14k + 49 = 0
(k-7)^2 = 0
k = 7