Given the points (6,-3) (-4,2):
Find the equation of a line that passes through the origin and is parallel to the line defined by the points. Please help me...thank u so much
the slope of the line through the two points is 5/-10 = -1/2.
So, what is the line through the origin with that slope?
Ans.- (x+2y=0)
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No any other line is parallel to the given line passes through origin.
So, the given line is only one line which passes through origin.
To find the equation of a line parallel to another line, we need to use the fact that parallel lines have the same slope.
First, let's find the slope of the line defined by the given points using the slope formula:
slope (m) = (y2 - y1) / (x2 - x1)
Let's substitute the coordinates of the given points into the formula:
m = (2 - (-3)) / (-4 - 6)
m = 5 / -10
m = -1/2
Now that we have the slope of the line, we can use it to find the equation of the line passing through the origin (0, 0). The equation of a line can be represented in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Since the line passes through the origin, the y-intercept is 0. Therefore, the equation of the line is:
y = -1/2x + 0
Simplifying the equation, we get:
y = -1/2x
So, the equation of the line passing through the origin and parallel to the line defined by the given points is y = -1/2x.