Solve for d

D(t)= -8cos (pi(t)/30)+8

solve what? d is just the definition of a function.

i mean the y value,change it to sin function

To solve for d, we need to isolate the variable d in the given equation D(t) = -8cos(pi(t)/30) + 8.

Here's how you can do it step-by-step:

1. Start with the equation: D(t) = -8cos(pi(t)/30) + 8.

2. Subtract 8 from both sides of the equation to isolate the cosine term: D(t) - 8 = -8cos(pi(t)/30).

3. Divide both sides of the equation by -8 to isolate the cosine term: (D(t) - 8)/-8 = cos(pi(t)/30).

4. Take the inverse cosine (arccos) of both sides of the equation to remove the cosine: arccos((D(t) - 8)/-8) = pi(t)/30.

5. Multiply both sides of the equation by 30/pi to isolate the variable t: (30/pi) * arccos((D(t) - 8)/-8) = t.

6. Now, we have the equation t = (30/pi) * arccos((D(t) - 8)/-8) as an expression for t.

Thus, to solve for d, you will need to substitute the desired values of t into the equation t = (30/pi) * arccos((D(t) - 8)/-8), and then evaluate it.