Find two mixed numbers that up to 16 but have a difference of 5???
To find two mixed numbers that add up to 16 and have a difference of 5, you can set up a system of equations.
Let's assume the first mixed number is represented by a whole number "x" and a fraction "y" and the second mixed number is represented by a whole number "a" and a fraction "b".
According to the given conditions, the sum of the two mixed numbers is 16:
x + y + a + b = 16 ---(Equation 1)
The difference between the two mixed numbers is 5:
(x + y) - (a + b) = 5 ---(Equation 2)
Now, we have a system of equations with two unknowns (x, y, a, b). We need to solve these equations to find the values of x, y, a, and b.
However, there are multiple pairs of mixed numbers that satisfy these conditions. Here is one possible solution:
Let's assume x = 8, y = 1/4, a = 2, and b = 3/4.
Substituting these values into Equation 1:
(8 + 1/4) + (2 + 3/4) = 8 ¼ + 2 ¾ = 10
Substituting these values into Equation 2:
(8 + 1/4) - (2 + 3/4) = 8 ¼ - 2 ¾ = 5
So, we have found two mixed numbers that add up to 16 and have a difference of 5: 8 ¼ and 2 ¾.
x= 10.5
using either equation to find Y
x + Y= 21
10.5 + Y=16
16-10.5
y= 5.50
check: x+y=21 10.5+5.50=16
x-y=5 10.5-5.50=5
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I don't feel alone anymore.... welcome to COMMONCORE math. Nana
2x= 10.5
using either equation to find Y
x + Y= 21
10.5 + Y=16
16-10.5
y= 5.50
check: x+y=21 10.5+5.50=16
x-y=5 10.5-5.50=5
Just treat them as x and y. No trick to the mixed numbers because it will happen automatically depending on the numbers use.
x + y = 16
x - y = 5
add the two equations
2x = 21
Can you finish from here?