The work done by 500 calories of heat in isothermal expansion of ideal gas is?
Its amazing 😊
To determine the work done by 500 calories of heat in an isothermal expansion of an ideal gas, we can use the formula:
Work = nRT ln(V2/V1)
Where:
- Work is the work done by the gas (in joules)
- n is the number of moles of gas
- R is the ideal gas constant (8.31 J/mol·K)
- T is the temperature of the gas (in Kelvin)
- V2 is the final volume of the gas
- V1 is the initial volume of the gas
However, the given information is in calories, so we need to convert calories to joules.
1 calorie = 4.184 joules
So, 500 calories = 500 * 4.184 joules = 2092 joules.
Next, we need additional information to calculate the work done, such as the number of moles of gas, the temperature, and the initial and final volumes.
Once you have this information, you can substitute the values into the formula to calculate the work done by 500 calories of heat in the isothermal expansion of the ideal gas.
Your textbook should have this:
One calorie is equivalent to 4.184 joules or J = 4.18 J/cal.
Work done(W) = 4.18 * 500 = 2090J