The acceleration of an electron in an electric field with a strength of 7.0 N/C is?
To find the acceleration of an electron in an electric field, we can use the equation:
acceleration = force / mass
where acceleration is measured in meters per second squared (m/s^2), force is measured in Newtons (N), and mass is the mass of the electron.
The force experienced by a charged particle in an electric field is given by:
force = charge x electric field strength
The charge of an electron is -1.6 x 10^-19 coulombs (C).
Substituting the given values into the equation, we have:
force = (-1.6 x 10^-19 C) x (7.0 N/C)
Now, we need to divide the force by the mass of an electron to find the acceleration. The mass of an electron is approximately 9.1 x 10^-31 kilograms (kg).
So, the acceleration of the electron in the given electric field is:
acceleration = [(-1.6 x 10^-19 C) x (7.0 N/C)] / (9.1 x 10^-31 kg)
Calculating the values, the acceleration of the electron is approximately 1.23 x 10^11 m/s^2.