A train starts from rest with an accelaration of 0.5 m/s (square) find its speed in km/h when it has moved throug 100m
V^2 = Vo^2 + 2a*d = 0 + 2*0.5*100 = 100.
V = 10 m/s.
V=10m/s * 1km/1000m * 3600s/h = 36 km/h.
To find the speed of the train, we can use the equation of motion:
v² = u² + 2as
Where:
v = final velocity (speed)
u = initial velocity (which is 0 since the train starts from rest)
a = acceleration, given as 0.5 m/s²
s = distance, given as 100 meters
Substituting the given values into the equation, we have:
v² = 0² + 2(0.5)(100)
v² = 0 + 100
v² = 100
To solve for v, we take the square root of both sides:
v = √100
v = 10 m/s (meters per second)
Now, let's convert the speed from meters per second to kilometers per hour. Since there are 1000 meters in a kilometer and 3600 seconds in an hour:
v (km/h) = v (m/s) × (3600/1000)
v (km/h) = 10 × 3.6
v (km/h) = 36 km/h
Therefore, the speed of the train when it has moved through 100 meters would be 36 km/h.