The age of the father is five times the age of the son.if the total ages of the father and son is 78, find the ages of the father and son.
If the son is x, the father is 5x. So,
x + 5x = 78
...
x+5x=6x
6x=78
78/6=13 son age
13x5= 65 father age
To solve this problem, we can use algebra. Let's assign variables to represent the ages of the father and the son.
Let's say the age of the son is S.
Since the age of the father is five times the age of the son, we can represent the father's age as 5S.
We know that the total ages of the father and son is 78.
So we can write the equation:
S + 5S = 78
Simplifying the equation, we get:
6S = 78
To find the value of S, we divide both sides by 6:
S = 78 / 6
S = 13
Therefore, the son's age is 13 years old.
To find the father's age, we substitute the value of S into our equation:
Father's age = 5S = 5 * 13 = 65
Therefore, the father's age is 65 years old.
Thus, the son is 13 years old, and the father is 65 years old.