In February, you have a balance of $80 in your bank account. Each month you deposit $20. Let January = 1, February = 2, and so on. Write an equation for this situation. Use the equation to find the balance in December.
y = 20(x – 4); $200
y - 80 = 20(x - 2); $280
y = 20(x – 4); $80
y – 80 = 20x; $20
The answer is B. I don't remember which unit this was in but I think its B.
The equation you will use is y - 80 = 20(x - 2); $280
y - 80 = 20(x - 2)
y = 20x - 40 + 80
y = 20x + 40 then factor to get,
y = 20(x + 2)
let x = 12 since December is the 12th month.
y = 20(12 + 2) --> y = 20(14)
y = 280
To find the equation for this situation, let's break down the given information step by step:
In February (represented by x = 2), you have a balance of $80. This gives us the starting point for our equation, which is y - 80.
Each month, you deposit $20. This means that for each month (x), you add $20 to your balance (y). Therefore, the expression for the deposits is 20(x - 2), where x - 2 represents the number of months after February.
Putting it all together, we get the equation:
y - 80 = 20(x - 2)
To find the balance in December (x = 12), substitute x = 12 into the equation and solve for y:
y - 80 = 20(12 - 2)
y - 80 = 20(10)
y - 80 = 200
y = 200 + 80
y = 280
Therefore, the balance in December is $280.