Two springs are set up on a table. The longer spring has a spring constant of 221 N/m and an initial length of 44.0cm. The shorter spring has a spring constant of 725 N/m and an initial length of 22.0cm. How far above the table is an 9.30kg ball when it reaches its equilibrium position? show the steps plzz

while walking behind a horse, a rancher walks 18.0 m (290degrees), then 25.0 m (340degrees) and finally 14.0 m (130 degrees)

A)Calculate the displacement of the rancher
b) if the rancher walks for 10 min, what is the average velocity of the walk?

John, Can you or any others help in my recent question I posted around 4pm?? Here is the question but go to my actual question I posted....

A person is standing on a 10-m bridge above a road. He wants to jump from the bridge and land in the bed of a truck that is approaching him at 30 m/s. In order to clear the bridge railing, he has to jump upward initially with a speed of 5 m/s. How far away should the truck be when he jumps in order for him to land in the bed?

To find the distance above the table that the ball is when it reaches its equilibrium position, we can use Hooke's law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The equation for Hooke's law is:

F = -kx

where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Since there are two springs, we can consider them as being connected in series. In a series connection, the effective spring constant (k_eff) is given by:

1/k_eff = 1/k_1 + 1/k_2

where k_1 and k_2 are the spring constants of the individual springs.

Given:
k_1 = 221 N/m
k_2 = 725 N/m

We can substitute these values into the equation to find the effective spring constant:

1/k_eff = 1/221 + 1/725

Now, we can solve for k_eff:

k_eff = 1 / (1/221 + 1/725)

Next, we need to consider the initial lengths of the springs. In the equilibrium position, the sum of their lengths is equal to the length of the ball from the table. So we have:

L_ball = L_spring1 + L_spring2

Where:
L_ball is the length of the ball from the table
L_spring1 is the initial length of the longer spring (44.0 cm)
L_spring2 is the initial length of the shorter spring (22.0 cm)

Now, we can substitute the values into the equation:

L_ball = 44.0 cm + 22.0 cm

L_ball = 66.0 cm

Finally, we can find the displacement x of the ball from its equilibrium position using Hooke's law:

F = -k_eff * x

The force F is given by the weight of the ball, which is equal to its mass times the acceleration due to gravity:

F = m * g

Where:
m is the mass of the ball (9.30 kg)
g is the acceleration due to gravity (9.81 m/s^2)

Substituting these values into the equation, we have:

m * g = -k_eff * x

Now, we can solve for x:

x = (m * g) / -k_eff

Substituting the known values:

x = (9.30 kg * 9.81 m/s^2) / -k_eff

Now, substitute the value of k_eff we found earlier:

x = (9.30 kg * 9.81 m/s^2) / -k_eff

Finally, calculate the value of x.