Julie has $11.10 in nickels and quarters. She has 24 more quarters than nickels. how many of each coin does she have?
add up the values. If there are n nickels, then they coins are worth
5n + 25(n+24) = 1110
OOOOOOOO I KNOW KNOW ITS I DONT KNOW
BY BUTTFACEFRESHTHEKID
To solve this problem, we can set up a system of equations.
Let's define two variables:
N = the number of nickels
Q = the number of quarters
From the given information, we have two equations:
1) Julie has $11.10 in nickels and quarters, so we can express this in terms of cents: 5N + 25Q = 1110 (since there are 100 cents in a dollar).
2) Julie has 24 more quarters than nickels: Q = N + 24.
We can substitute equation 2) into equation 1) to eliminate one variable and solve for the other variable:
5N + 25(N + 24) = 1110
5N + 25N + 600 = 1110
30N + 600 = 1110
30N = 510
N = 17
Now that we know N = 17, we can substitute this back into equation 2) to find Q:
Q = 17 + 24
Q = 41
Therefore, Julie has 17 nickels and 41 quarters.