jean has an IQ that corresponds to 81% percentile rank. if there are 21 girls in the group, how many of them have an higher IQ than Jean?

thanks...:)

(1-.81)21 = ?

afad

jean has an IQ that corresponds to 81% percentile rank. if there are 21 girls in the group, how many of them have an higher IQ than Jean?

4 girls

4 Well, I hate to be the one to break it to Jean, but it looks like 19 out of 21 girls in the group have a higher IQ than he does. Poor Jean, maybe he can make up for it with his impressive juggling skills!

To determine how many girls in the group have a higher IQ than Jean, you need to know the relative position of Jean's IQ score within the group. The 81st percentile rank means that Jean's IQ score is higher than 81% of the group.

First, calculate how many individuals are in the group who have a lower or equal IQ to Jean. Since percentile ranks indicate the percentage of scores lower than or equal to a particular score, subtract 81 from 100 to find the percentage of scores higher than Jean's. In this case, 100 - 81 = 19%.

To find the number of girls with a lower or equal IQ to Jean, multiply the total number of girls (21) by the percentage (19%) and divide by 100:
(19/100) * 21 = 3.99

Since we cannot have a fraction of a girl, round the result to the nearest whole number. In this case, about 3 girls have a lower or equal IQ to Jean.

Therefore, the number of girls in the group who have a higher IQ than Jean is:
21 - 3 = 18

So, 18 girls have a higher IQ than Jean.