A 0.27 kf bullet is fired from a 4.1kg gun the bullet leaves the gun at a speed of 200m/s what os the recoil speed of the gun
conserve momentum
.27*200 = 4.1v
To find the recoil speed of the gun, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the event should equal the total momentum after the event.
1. Calculate the initial momentum of the bullet:
Initial momentum of the bullet = mass of the bullet × velocity of the bullet
Given:
Mass of the bullet = 0.27 kg
Velocity of the bullet = 200 m/s
Initial momentum of the bullet = 0.27 kg × 200 m/s = 54 kg·m/s
2. Calculate the total momentum after the event:
Since only the bullet is moving after the event, the total momentum will be equal to the momentum of the bullet.
Total momentum after the event = momentum of the bullet = 54 kg·m/s
3. Calculate the final velocity of the gun:
Final momentum of the gun = Total momentum after the event = 54 kg·m/s
Final velocity of the gun = Final momentum of the gun / mass of the gun
Given:
Mass of the gun = 4.1 kg
Final velocity of the gun = 54 kg·m/s / 4.1 kg ≈ 13.171 m/s
Therefore, the recoil speed of the gun is approximately 13.171 m/s.