I just need someone to check over my answers, I'm pretty confident in all of them!
In which six-membered hydrocarbon rings are all of the C-C-C angles roughly the same, i.e., within 1o? Select ALL that apply.
Question 1 options:
A)cyclohexane
B)cyclohexene
C)1,3-cyclohexadiene
D)benzene
>>>I chose A and D
Question 2 (1 point) Question 2 Saved
Which six-membered hydrocarbon ring(s) is(are) planar, i.e., all six C atoms are in the same plane? Select ALL that apply.
Question 2 options:
A)cyclohexane
B)cyclohexene
C)1,3-cyclohexadiene
D)benzene
>>>I chose only D
Question 3 (0.5 points)What are the interior angles, in degrees, in a regular hexagon?
Your Answer:
120
Question 4 (0.5 points) Question 4 Saved
Which hybridization of C results in bond angles that are the same as those for a regular hexagon, thus allowing the ring to be planar?
Question 4 options:
A)sp
B)sp2
C)sp3
>>>I chose B
Thanks
For Question 1, you were asked to select all the six-membered hydrocarbon rings in which all the C-C-C angles are roughly the same. Let's go through each option:
A) Cyclohexane: In cyclohexane, all the C-C-C angles are approximately 109.5 degrees, which is close to the tetrahedral angle. Therefore, this option is correct.
B) Cyclohexene: In cyclohexene, there is a double bond present, which introduces a significant distortion in the bond angles. Thus, the C-C-C angles are not all the same. Therefore, this option is incorrect.
C) 1,3-cyclohexadiene: Similar to cyclohexene, the presence of double bonds in this compound also leads to distortion in the bond angles. Hence, this option is incorrect.
D) Benzene: In benzene, all the C-C-C angles are equal, and each angle is around 120 degrees, which is close to a regular hexagon. Therefore, this option is correct.
Therefore, the correct answers for Question 1 are A) cyclohexane and D) benzene.
For Question 2, the objective was to identify the six-membered hydrocarbon ring(s) that are planar, meaning all the six C atoms are in the same plane. Let's analyze the options:
A) Cyclohexane: In cyclohexane, the C-C-C angles are approximately 109.5 degrees, indicating that it is not planar. Therefore, this option is incorrect.
B) Cyclohexene: Similar to cyclohexane, the presence of a double bond causes distortion in the bond angles, making it non-planar. Therefore, this option is incorrect.
C) 1,3-cyclohexadiene: Again, the presence of double bonds leads to deviation from planarity. Therefore, this option is incorrect.
D) Benzene: In benzene, all the C atoms lie in the same plane, and the molecule exhibits planarity. Therefore, this option is correct.
Hence, the only correct answer for Question 2 is D) benzene.
For Question 3, you were asked to determine the interior angles in a regular hexagon. A regular hexagon is a polygon with six sides and six equal angles. To find the interior angles, you can use the formula: (n-2) * 180 / n, where n represents the number of sides. In this case, n = 6, so the formula becomes (6-2) * 180 / 6 = 4 * 180 / 6 = 720 / 6 = 120 degrees. Therefore, your answer of 120 is correct.
For Question 4, the goal was to identify the hybridization of carbon that results in bond angles the same as a regular hexagon, allowing the ring to be planar. Let's examine the options:
A) sp: The sp hybridization leads to a linear arrangement of the atoms and does not result in bond angles similar to those of a regular hexagon. Thus, this option is incorrect.
B) sp2: The sp2 hybridization leads to a trigonal planar arrangement of the atoms, where the bond angles are approximately 120 degrees. This arrangement matches the bond angles of a regular hexagon, allowing the ring to be planar. Hence, this option is correct.
C) sp3: The sp3 hybridization results in a tetrahedral arrangement of the atoms with bond angles of about 109.5 degrees. Therefore, this option does not match the bond angles of a regular hexagon and is incorrect.
Therefore, the correct answer for Question 4 is B) sp2.
Overall, your answers for Questions 1, 2, 3, and 4 are correct. Well done!
Based on your answers, here is a review:
Question 1:
In which six-membered hydrocarbon rings are all of the C-C-C angles roughly the same, i.e., within 1o? Options were A) cyclohexane, B) cyclohexene, C) 1,3-cyclohexadiene, and D) benzene.
Your choices: A) cyclohexane and D) benzene.
Correct choices: A) cyclohexane and D) benzene.
Your answers are correct for this question.
Question 2:
Which six-membered hydrocarbon ring(s) is(are) planar, i.e., all six C atoms are in the same plane? Options were A) cyclohexane, B) cyclohexene, C) 1,3-cyclohexadiene, and D) benzene.
Your choices: D) benzene.
Correct choices: D) benzene.
Your answer is correct for this question.
Question 3:
What are the interior angles, in degrees, in a regular hexagon?
Your answer: 120 degrees.
Correct answer: 120 degrees.
Your answer is correct for this question.
Question 4:
Which hybridization of C results in bond angles that are the same as those for a regular hexagon, thus allowing the ring to be planar? Options were A) sp, B) sp2, and C) sp3.
Your choice: B) sp2.
Correct choice: B) sp2.
Your answer is correct for this question.
Overall, your answers are all correct. Well done!