how do you calculate probabily or this problem.
A bag has 8 red, 6blue, 2 yellow and 7 green marbles. What is the probability of selecting a red, not replacing it and selecting a green?
6/21 * 7/21 =42/21
Total Marbles = 23
probability of selecting red = 8/23
probability of selecting green = 7/23
so after you chose red there are only 22 marbles left total. This means the probability of selecting green is 7/22
prob(red, then green)
= (8/23)(7/22)
= 28/253
To calculate the probability of selecting a red marble, not replacing it, and then selecting a green marble, you need to follow these steps:
Step 1: Calculate the probability of selecting a red marble.
In this case, there are 8 red marbles out of a total of 8 + 6 + 2 + 7 = 23 marbles in the bag. So the probability of selecting a red marble is 8/23.
Step 2: After selecting a red marble, you do not replace it. So now there are 7 green marbles out of a total of 23 - 1 = 22 marbles left in the bag. So the probability of selecting a green marble is 7/22.
Step 3: To find the probability of two independent events happening together, you multiply their probabilities. Therefore, the probability of selecting a red marble and then a green marble is (8/23) * (7/22).
Step 4: Simplify the fraction if necessary. In this case, you can divide both numerator and denominator by their greatest common divisor, which is 1. Thus, the final probability is 56/506.
So, the probability of selecting a red marble, not replacing it, and then selecting a green marble is 56/506.