the number of blocks has 9 in the ones place.The number in the hundreds place is onemore than the number in the tens place.Those two numbers equal 11.How many blocks are there?

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To solve this problem, we can break down the information provided and use algebra to find the answer.

Let's use variables to represent the unknowns:
Let x represent the number in the ones place.
Let y represent the number in the tens place.
Let z represent the number in the hundreds place.

Based on the given information:
1. The number of blocks has 9 in the ones place, so x = 9.
2. The number in the hundreds place is one more than the number in the tens place, so z = y + 1.
3. The sum of the numbers in the hundreds and tens place equals 11, so z + y = 11.

Now, let's substitute the values of x and z into the equation z + y = 11:
(y + 1) + y = 11
2y + 1 = 11
2y = 10
y = 5

We have found the value of y, which is 5.

Now, let's substitute the value of y back into z = y + 1:
z = 5 + 1
z = 6

We have found the value of z, which is 6.

So, there are 9 blocks in the ones place (x = 9), 5 blocks in the tens place (y = 5), and 6 blocks in the hundreds place (z = 6).

Therefore, the total number of blocks is 9 + 5 + 6 = 20 blocks.