how many joules are needed to completely melt 25 grams of ice at 0 degree celcius?
To calculate the amount of energy needed to completely melt 25 grams of ice at 0 degrees Celsius, we can use the equation:
Q = m * ΔHf
Where:
Q is the heat energy required (in joules)
m is the mass of the substance (in grams)
ΔHf is the heat of fusion (specific latent heat) for water, which is 334 J/g
Plugging in the values:
m = 25 grams
ΔHf = 334 J/g
Q = 25 grams * 334 J/g
Q = 8350 joules
Therefore, 8350 joules are needed to completely melt 25 grams of ice at 0 degrees Celsius.
To calculate the amount of energy required to completely melt a given amount of ice, you need to know the heat of fusion (also called the molar heat of fusion) of water and the mass of ice to be melted.
The heat of fusion of water is the amount of energy needed to change a substance from a solid to a liquid at its melting point. For water, the heat of fusion is approximately 334 J/g. This means it takes 334 joules of energy to melt 1 gram of ice at 0 degrees Celsius.
Given that you have 25 grams of ice, you can calculate the energy needed to melt it completely using the following formula:
Energy = Mass of ice (in grams) x Heat of fusion of water
Energy = 25 g x 334 J/g
Energy = 8350 J
Therefore, it would require 8350 joules of energy to completely melt 25 grams of ice at 0 degrees Celsius.