1) Balance the following equation in basic conditions:

2CoCl2 + Na2O2 --> 2Co(OH)3 + 4Cl^- + 2Na^+

2) Balance the following equation in acidic conditions:

H3AsO3 + I2 --> H3AsO4 +2I^-

To balance an equation in basic conditions, follow these steps:

Step 1: Start by balancing the elements other than hydrogen (H) and oxygen (O). In this case, we have Cobalt (Co), Chlorine (Cl), and Sodium (Na).

2CoCl₂ + Na₂O₂ → 2Co(OH)₃ + 4Cl⁻ + 2Na⁺

Step 2: Balance the oxygen atoms by adding water (H₂O) to the side that needs more oxygen. In this case, we have 2 oxygen atoms on the left side and 3 oxygen atoms on the right side, so we need to add water to the left side.

2CoCl₂ + Na₂O₂ + H₂O → 2Co(OH)₃ + 4Cl⁻ + 2Na⁺

Step 3: Balance the hydrogen atoms by adding hydroxide ions (OH⁻) to the side that needs more hydrogen. In this case, we have 1 hydrogen atom on the left side and 6 hydrogen atoms on the right side, so we need to add 5 hydroxide ions to the left side.

2CoCl₂ + Na₂O₂ + H₂O + 5OH⁻ → 2Co(OH)₃ + 4Cl⁻ + 2Na⁺

Step 4: Finally, balance the charges by adding appropriate counter ions to the opposite side. In this case, we need to add 4 sodium ions (Na⁺) on the left side to balance the 4 chloride ions (Cl⁻) on the right side.

2CoCl₂ + Na₂O₂ + H₂O + 5OH⁻ + 4Na⁺ → 2Co(OH)₃ + 4Cl⁻ + 2Na⁺

The balanced equation in basic conditions is:

2CoCl₂ + Na₂O₂ + H₂O + 5OH⁻ + 4Na⁺ → 2Co(OH)₃ + 4Cl⁻ + 2Na⁺