What is the slope of the line that passes through the pair of points (3/2,-2) and (-3,7/3)
a.-27/26
b.-26/27
c.26/27
d.27/26
please help me
anybody up that knows the answer
(3/2,-2), (-3,7/3).
Slope = (y2-y1)/(x2-x1).
Slope = (7/3-(-2))/(-3-3/2) =
(7/3+2)/(-6/2-3/2) = (7/3+6/3)/(-9/2) =
(13/3)/(-9/2) = 13/3 * (-2/9) = -26/27.
To find the slope of a line that passes through two points, you can use the formula:
slope = (y2 - y1) / (x2 - x1)
In this case, the coordinates of the first point are (3/2, -2), which means x1 = 3/2 and y1 = -2. The coordinates of the second point are (-3, 7/3), which means x2 = -3 and y2 = 7/3.
We can plug these values into the slope formula:
slope = (7/3 - (-2)) / (-3 - 3/2)
Next, we simplify the numerator and denominator:
slope = (7/3 + 2) / (-6/2 - 3/2)
slope = (7/3 + 6/3) / (-9/2)
slope = 13/3 / (-9/2)
To divide by a fraction, we can multiply by its reciprocal:
slope = 13/3 * (-2/9)
slope = -26/27
The slope of the line that passes through the pair of points (3/2, -2) and (-3, 7/3) is -26/27.
Therefore, the correct answer is b. -26/27.