The diffusion rate for a solute is 4.0E-11 kg/s in a solvent-filled channel that has a cross-sectional area of 0.50 cm^2 and a length of 0.220 cm.
What would be the diffusion rate m/t in a channel with a cross-sectional area of 0.30 cm^2 and a length of 0.10 cm?
m/t= ??E-11 kg/s
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Pretty sure the equation DA∆C/L = m/t is involved...
To find the diffusion rate in the new channel, you can use the formula:
D1/A1 * L1 = D2/A2 * L2
where:
D1 = Diffusion rate in the first channel (4.0E-11 kg/s)
A1 = Cross-sectional area of the first channel (0.50 cm^2)
L1 = Length of the first channel (0.220 cm)
D2 = Diffusion rate in the new channel (unknown)
A2 = Cross-sectional area of the new channel (0.30 cm^2)
L2 = Length of the new channel (0.10 cm)
Rearranging the formula to solve for D2, we have:
D2 = D1/A1 * L1 * A2/L2
Substituting the given values into the formula:
D2 = (4.0E-11 kg/s) / (0.50 cm^2) * (0.220 cm) * (0.30 cm^2) / (0.10 cm)
Now, let's calculate the value:
D2 = (4.0E-11 kg/s) / (0.50 cm^2) * (0.220 cm) * (0.30 cm^2) / (0.10 cm)
≈ 5.28E-11 kg/s
Therefore, the diffusion rate m/t in the new channel is approximately 5.28E-11 kg/s.