A 4" by 6" photograph is in a frame 3/4" wide. What is the outer perimeter of the framed photograph?
5.5 inches 7.5 inches perimeter is 13 inches
4 + [2 * (3/4)] = ______ inches
6 + [2 * (3/4)] = _______inches
P = 2L + 2W
P = ?
4+2x.75=5.5
6+2x.75=7.5
5.5+7.5=13^2
P=26inches
1.
Leland wants to paint a portrait for his parents using a photograph of them that is 5 inches wide by 8 inches high. He wants the portrait to be proportional to the photograph and 42 inches high. Which proportion can Leland use to find w, the width he needs to use to make the portrait proportion
To find the outer perimeter of the framed photograph, we first need to calculate the dimensions of the framed photograph.
The photograph is a rectangle with dimensions 4 inches by 6 inches. The frame is 3/4 inch wide on all sides.
To get the dimensions of the framed photograph, we need to add twice the width of the frame to each side of the photograph.
The width of the framed photograph will be:
4 inches + (2 × 3/4) inches + (2 × 3/4) inches = 4 inches + 3/2 inches + 3/2 inches = 4 inches + 1.5 inches + 1.5 inches = 4 inches + 3 inches = 7 inches
Similarly, the length of the framed photograph will be:
6 inches + 3/2 inches + 3/2 inches = 6 inches + 1.5 inches + 1.5 inches = 6 inches + 3 inches = 9 inches
Now that we have the dimensions of the framed photograph, we can calculate the outer perimeter by adding up all four sides:
Perimeter = 2 × (Length + Width)
Perimeter = 2 × (9 inches + 7 inches)
Perimeter = 2 × 16 inches
Perimeter = 32 inches
Therefore, the outer perimeter of the framed photograph is 32 inches.