Find coordinates of the points on the given curve at which it's gradient has the given value.
Y=x^3+x^2
Gradient = 1
I know that
dy/dx = 3x^2+2x
I'm not sure what to do next.
Please help
Thankyou 😘
Well, when is that slope equal to 1 ?
3 x^2 + 2 x - 1 = 0
(3x-1)(x+1) = 0
x = 1/3 or x = -1