The length of a rectangle is 5cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the dimensions of the rectangle.
same type of question as the one above, just change the numbers.
To solve this problem, we can set up a system of equations based on the given information.
Let's say the width of the rectangle is w cm. According to the problem, the length of the rectangle is 5cm more than twice the width, which can be expressed as 2w + 5 cm.
The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
In this case, we know that the perimeter of the rectangle is 34 cm. So we can set up the equation:
34 = 2(2w + 5 + w)
Simplifying the equation, we have:
34 = 2(3w + 5)
34 = 6w + 10
34 - 10 = 6w
24 = 6w
w = 24/6
w = 4
Now that we know the width is 4 cm, we can substitute this value back into one of the equations to find the length:
l = 2w + 5
l = 2(4) + 5
l = 8 + 5
l = 13
So, the dimensions of the rectangle are width = 4 cm and length = 13 cm.