Concentrated sulfuric acid is 18.0 M. If you are asked to make a 1L solution of 6M sulfuric acid. How much water (L) and how much acid (L) should be added to make this solution?

mL1 x M1 = mL2 x M2

mL1 x 18 = 1000 mL x 6 M
Take the volume calculated, pipet that into a 1000 mL volumetric flask, make to the mark. Shake thoroughly and stopper.

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To make a 1L solution of 6M sulfuric acid from the concentrated 18.0 M sulfuric acid, we can use the concept of dilution.

The formula for dilution is given as:

M1V1 = M2V2

Where:
M1 = initial concentration of the acid
V1 = volume of the acid you want to take out
M2 = final concentration of the diluted solution
V2 = final volume of the diluted solution

In this case, we know:
M1 = 18.0 M (concentrated sulfuric acid)
V1 = ? (volume of concentrated acid to be taken out)
M2 = 6.0 M (desired concentration of diluted sulfuric acid)
V2 = 1 L (desired final volume of the solution)

Rearranging the formula, we have:
V1 = (M2 * V2) / M1

Plugging in the given values, we get:
V1 = (6.0 M * 1 L) / 18.0 M
V1 = 0.33 L

So, to make a 1L solution of 6M sulfuric acid, you need to take out 0.33L (or 330 mL) of the concentrated sulfuric acid.

To determine the volume of water required, you can subtract the volume of concentrated acid from the final desired volume:
Volume of water = V2 - V1
Volume of water = 1 L - 0.33 L
Volume of water = 0.67 L

Therefore, you should add 0.33 L of the concentrated sulfuric acid and 0.67 L of water to make a 1L solution of 6M sulfuric acid.