a 10.0 ml sample of a hcl solution is titrated with 32.6 ml of a 0.155 m naoh solution. what is the equation for the neutralization reaction?
Hint: Find the caps key on your keyboard and learn to use it. CO, Co, and co all have different meanings.
NaOH + HCl ==> NaCl + H2O
To determine the neutralization reaction equation between HCl (hydrochloric acid) and NaOH (sodium hydroxide), we need to consider their respective chemical formulas and the reaction mechanism.
HCl is a strong acid, and its chemical formula represents one molecule of hydrochloric acid, which dissociates in water to form one hydrogen ion (H+) and one chloride ion (Cl-):
HCl(aq) → H+(aq) + Cl-(aq)
NaOH is a strong base, and its chemical formula represents one molecule of sodium hydroxide, which dissociates in water to form one sodium ion (Na+) and one hydroxide ion (OH-):
NaOH(aq) → Na+(aq) + OH-(aq)
In a neutralization reaction between an acid and a base, the hydrogen ion (H+) from the acid reacts with the hydroxide ion (OH-) from the base to form water (H2O):
H+(aq) + OH-(aq) → H2O(l)
In this case, the reaction occurs between the 10.0 mL of HCl solution and the 32.6 mL of 0.155 M NaOH solution. Since the reaction is stoichiometric, it means that one mole of HCl reacts with one mole of NaOH.
To find the balanced equation, we need to ensure an equal number of hydrogen ions (H+) and hydroxide ions (OH-) on each side. Thus, the balanced equation for the neutralization reaction between HCl and NaOH can be written as:
HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
Where NaCl represents sodium chloride, which is a salt formed by the combination of sodium ions (Na+) and chloride ions (Cl-).