The question is: The area of a rectangle is given by the expression 8x+44y. Length is 2x+11y. What is width? I answered 4x & 4y, yet that was wrong. Can you help explain why?
Thanks
area = lw
w = area/l
= (8x+44y)/(2x+11y)
= 4(2x + 11y)/(2x+11y)
= 4
or what must I multiply 2x+11y by to get 8x+44y ?
how about by 4
(2x+11y) (w) = 8 x + 44 y
w = (8 x + 44 y) / (2 x + 11 y)
= 4 (2 x + 11 y) / (2 x + 11 y)
= 4
To find the width of a rectangle, we need to divide the area by the length. In this case, the area is given as 8x + 44y, and the length is 2x + 11y. So, to find the width (W), we can use the formula:
W = Area / Length
Substituting the given values, we have:
W = (8x + 44y) / (2x + 11y)
To simplify this expression, we can divide each term of the numerator (8x + 44y) by the common factor 4 and each term of the denominator (2x + 11y) by the common factor 1:
W = (4(2x + 11y)) / (1(2x + 11y))
Now we can cancel out the common factor (2x + 11y) from the numerator and the denominator:
W = 4
This means that the width of the rectangle is 4. Therefore, the answer is not 4x and 4y, but simply 4.