The value of 4x^3-x/(2x+1)(6x-3)
when x=9999
If 7 men working 7 hrs a day for each of 7 days produce 7 units of work, then the units of work produced by 5 men working 5 hrs a day for each of 5 days is?
Pls help***
assuming you mean
(4x^3-x)/((2x+1)(6x-3))
= (x(2x-1)(2x+1))/(3(2x+1)(2x-1))
= x/3
= 3333
well,
7 men for 7 hrs for 1 day = 1 work unit
7 men for 1 hr for 1 day = 1/7 wu
1 man for 1 hour for 1 day = 1/49 wu
5men * 5hrs * 5days = 125/49 wu
or, just do the ratios in-line
(5/7)(5/7)(5/7)=(5/7)^3*(7) = 125/49
Thnx
To find the value of 4x^3-x/(2x+1)(6x-3) when x=9999, you can substitute the value of x into the expression and simplify it step by step.
Step 1: Substitute the value of x into the expression:
4(9999)^3 - 9999 / [(2(9999)+1)(6(9999)-3)]
Step 2: Simplify the expression:
= 4(9999)^3 - 9999 / [(19998+1)(59994-3)]
= 4(9999)^3 - 9999 / [(19999)(59991)]
Step 3: Calculate the value of (9999)^3:
= 4(9999)(9999)(9999) - 9999 / [(19999)(59991)]
Step 4: Calculate the value of (9999)(9999):
= 4(99990001)(9999) - 9999 / [(19999)(59991)]
Step 5: Calculate the value of (99990001)(9999):
= 3999600389999 - 9999 / [(19999)(59991)]
Step 6: Subtract 9999 from 3999600389999:
= 3999600379999 / [(19999)(59991)]
Therefore, the value of 4x^3 - x/(2x+1)(6x-3) when x=9999 is 3999600379999 / [(19999)(59991)].
Now, let's move on to the next question.
If 7 men working 7 hours a day for each of 7 days produce 7 units of work, we can use the concept of "man-hours" to find the units of work produced by 5 men working 5 hours a day for each of 5 days.
Step 1: Find the total man-hours for the first scenario:
7 men * 7 hours/day * 7 days = 343 man-hours
Step 2: Calculate the units of work produced per man-hour:
7 units / 343 man-hours = 1/49 unit per man-hour
Step 3: Find the total man-hours for the second scenario:
5 men * 5 hours/day * 5 days = 125 man-hours
Step 4: Multiply the total man-hours by the units of work produced per man-hour:
125 man-hours * (1/49 unit per man-hour) = 125/49 units
Therefore, the units of work produced by 5 men working 5 hours a day for each of 5 days is 125/49 units.
Sure, I can help you with both questions.
1. The value of the expression when x = 9999:
To find the value of the expression 4x^3 - x / ((2x+1)(6x-3)) when x = 9999, we substitute the value of x into the expression and simplify it.
First, let's substitute x = 9999 into the expression:
4(9999)^3 - 9999 / ((2(9999)+1)(6(9999)-3))
Next, we simplify the expression:
= 4 * (9999)^3 - 9999 / ((2 * 9999 + 1)(6 * 9999 - 3))
= 4 * 9999000199990003999600019999 - 9999 / ((19998)(59994))
= 3999600079996002399840039996 - 9999 / (19998 * 59994)
= 3999600079996002399840039996 - 9999 / 1199512008
= 3999600079996002399840039996 - 0.0000083333291669444 (approximation)
So, the value of the expression when x = 9999 is approximately 3.99960008 × 10^27.
2. Units of work produced by 5 men working 5 hours a day for 5 days:
Given that 7 men working 7 hours a day for 7 days produce 7 units of work, we can use this information to find the units of work produced by 5 men working 5 hours a day for 5 days.
The number of units produced by one man in one hour is calculated as:
(7 units) / (7 men x 7 hours) = 1/7 unit/hour
Now, if we have 5 men working 5 hours a day for 5 days, we can calculate the units of work produced as follows:
(5 men) x (5 hours) x (5 days) x (1/7 unit/hour) = 125/7 units
Therefore, 5 men working 5 hours a day for 5 days will produce approximately 17.857 units of work.