3.A brown flower pot is dropped from an open window from the top floor of a brick apartment building on a Sunday afternoon in April. It fell 3.00 seconds before crashing into multiple pieces on the wet sidewalk below. How far did the flower pot fall?

To find the distance the flower pot fell, we can use the equation for free fall:

Distance (d) = 1/2 * acceleration due to gravity (g) * time squared (t^2)

The acceleration due to gravity is approximately 9.8 meters per second squared.

Plugging in the values:

d = 1/2 * 9.8 m/s^2 * (3.00 s)^2
d = 1/2 * 9.8 m/s^2 * 9.00 s^2
d = 0.5 * 9.8 m/s^2 * 9.00 s^2
d = 44.1 m

Therefore, the flower pot fell approximately 44.1 meters.

To calculate the distance the flower pot fell, we can use the kinematic equation:

d = 0.5 * a * t^2

Where:
d = distance
a = acceleration due to gravity
t = time

In this case, we know that the flower pot fell for 3.00 seconds before crashing. The acceleration due to gravity is approximately 9.8 m/s^2.

Plugging the values into the equation:

d = 0.5 * 9.8 * (3.00)^2
= 0.5 * 9.8 * 9
= 44.1 meters

Therefore, the flower pot fell approximately 44.1 meters before crashing into multiple pieces on the wet sidewalk below.