If 5.29 g of CuNO3 is dissolved in water to make a 0.370 M solution, what is the volume of the solution?

I assume you really meant CuNO3 and not Cu(NO3)2.

mols CuNO3 = grams/molar mass = ?
Then M CuNO3 = mols CuNO3/L CuNO3 solution. You know M and mols, solve for L.

To find the volume of the solution, we can use the equation:

Molarity (M) = Moles (mol) / Volume (L)

First, we need to find the number of moles of CuNO3.

To do this, we can use the formula:

Moles (mol) = Mass (g) / Molar mass (g/mol)

The molar mass of CuNO3 can be calculated by adding up the atomic masses of copper (Cu), nitrogen (N), and three oxygen (O) atoms:

Cu: 63.55 g/mol
N: 14.01 g/mol
O (3 atoms): 16.00 g/mol × 3 = 48.00 g/mol

Molar mass of CuNO3 = 63.55 g/mol + 14.01 g/mol + 48.00 g/mol = 125.56 g/mol

Now we can calculate the number of moles:

Moles (mol) = 5.29 g / 125.56 g/mol

Next, we can use the molarity equation to find the volume of the solution:

0.370 M = Moles (mol) / Volume (L)

Rearranging the equation to solve for volume:

Volume (L) = Moles (mol) / Molarity (M)

Now we can substitute the values we found into the equation:

Volume (L) = (5.29 g / 125.56 g/mol) / 0.370 mol/L

Calculating the value:

Volume (L) = 0.113 L

Therefore, the volume of the solution is 0.113 L (or 113 mL).