The perimeter of a rectangular garden is 62 m.If the length is 3 meters longer than the width,what is the width of the garden?

P = 2L + 2W

62 = 2(W + 3) + 2W

62 = 4W + 6

56 = 4W

14 = W

Let's assume the width of the garden is "x" meters.

According to the given information, the length of the garden is 3 meters longer than the width, so the length can be represented as "x+3" meters.

The formula for the perimeter of a rectangle is given by:
Perimeter = 2(length + width)

In this case, the perimeter is given as 62 meters. Substituting the given values into the formula, we have:
62 = 2(x + x+3)

Simplifying the equation:
62 = 2(2x+3)

Expanding the brackets:
62 = 4x + 6

Now, let's solve for x by isolating it on one side of the equation:
62 - 6 = 4x
56 = 4x

Finally, divide both sides by 4 to solve for x:
56/4 = x
14 = x

Therefore, the width of the garden is 14 meters.

To solve this problem, we can use the formula for the perimeter of a rectangle: P = 2(l + w), where P is the perimeter, l is the length, and w is the width.

Let's represent the width of the garden as x. According to the problem, the length is 3 meters longer than the width, so the length can be represented as x + 3.

The formula for the perimeter of the garden becomes: 62 = 2(x + (x + 3)).

Simplifying the equation, we have: 62 = 2(2x + 3).

Using the distributive property, we get: 62 = 4x + 6.

Subtracting 6 from both sides of the equation, we have: 56 = 4x.

Now, we divide both sides of the equation by 4 to solve for x: x = 14.

Therefore, the width of the garden is 14 meters.