Calculate the volume occupied by 7g of nitrogen gas at 27 degree c and 750 mm of hg pressure
Use PV = nRT with n = g N2/molar mass N2.
Remember T must be in kelvin.
0.00821
0.00821Litters
To calculate the volume occupied by 7g of nitrogen gas at 27 degrees Celsius and 750 mmHg of pressure, you will need to use the ideal gas equation.
The ideal gas equation is:
PV = nRT
Where:
P = pressure (in this case, 750 mmHg)
V = volume (which is what we are trying to calculate)
n = moles of gas (which we can calculate using the mass of the gas)
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in this case, converted to Kelvin)
First, we need to calculate the number of moles of nitrogen gas using its mass and molar mass.
The molar mass of nitrogen (N₂) is 28 g/mol (2 * 14 g/mol).
Moles = Mass / Molar mass
Moles = 7 g / 28 g/mol
Moles = 0.25 mol
Next, convert the temperature from Celsius to Kelvin.
Temperature(K) = Temperature(°C) + 273.15
Temperature(K) = 27 °C + 273.15
Temperature(K) = 300.15 K
Now we have all the necessary information to calculate the volume.
PV = nRT
V = (nRT) / P
V = (0.25 mol * 0.0821 L·atm/(mol·K) * 300.15 K) / 750 mmHg
Note: It is important to convert the pressure from mmHg to atm by dividing by 760 mmHg/atm.
V = (0.25 mol * 0.0821 L·atm/(mol·K) * 300.15 K) / (750 mmHg / 760 mmHg/atm)
V = (0.25 * 0.0821 * 300.15) / (750 / 760)
V = 6.143 L
So, the volume occupied by 7g of nitrogen gas at 27 degrees Celsius and 750 mmHg of pressure is approximately 6.143 liters.