what is the mass in amu of 3.12 moles of Ba(NO3)2?
To find the mass in atomic mass units (amu) of 3.12 moles of Ba(NO3)2, you need to know the molar mass of Ba(NO3)2 and then multiply it by the number of moles.
Here's how you can calculate it:
1. Find the molar mass of Ba(NO3)2:
- Look up the atomic masses of each element in the compound (Ba = 137.33 amu, N = 14.01 amu, O = 16.00 amu).
- Multiply the atomic mass of each element by the number of atoms present in the compound.
- Barium (Ba) has a subscript of 1, so its contribution is 1 × 137.33 amu.
- Nitrogen (N) has a subscript of 1, so its contribution is 1 × 14.01 amu.
- Oxygen (O) has a subscript of 3 (from NO3), so its contribution is 3 × 16.00 amu.
- Add together the contributions of each element to find the molar mass of Ba(NO3)2.
2. Multiply the molar mass by the number of moles:
- Multiply the molar mass (in grams/mole) calculated above by the number of moles (3.12 mol).
- The resulting value will be the mass of 3.12 moles of Ba(NO3)2 in grams.
Finally, since the question specifically asks for the mass in atomic mass units (amu), you'll need to divide the mass in grams by the molar mass of hydrogen (1.00784 amu) to convert it to amu.
Keep in mind that the molar mass of Ba(NO3)2 and the molar mass of hydrogen may be subject to slight variations depending on the periodic table and its conventions used.