Can someone check my answers
when a skydiver jumps from an airplane, the distance d in feet the diver falls in t seconds before opening the parachute is given by the formula d=16t2. the formula assumes that there is no air resistance. find the time it takes a skydiver to fall 1,551 ft before opening the parachute. round to the nearest tenth.
A: 9.7s
B: 9.8s
C: 9.9s
D: 2.5 s
Is the answer B?
the formula v = 64h can be used to find the velocity, v, in feet per second, of an object that has fallen h feet. find the velocity of an object that has fallen 75 feet. round to the nearest tenth
A: 6.9 ft/s
B: 69.2 ft/s
C: 69.4 ft/s
D: 69.3 ft/s
Is the answer D?
See previous post: Thu, 11-12-15, 11:06 PM.
To find the time it takes a skydiver to fall 1,551 ft before opening the parachute, we can use the formula d = 16t^2. We need to solve the equation for t when d = 1,551.
The equation becomes:
1551 = 16t^2
To solve for t, divide both sides of the equation by 16:
1551/16 = t^2
t^2 = 96.9375
To isolate t, take the square root of both sides:
sqrt(96.9375) = t
t ≈ 9.84375
Rounded to the nearest tenth, the time it takes the skydiver to fall 1,551 ft before opening the parachute is approximately 9.8 seconds.
Therefore, the answer is B: 9.8s.
Now let's move on to the second question.
The formula v = 64h can be used to find the velocity, v, in feet per second, of an object that has fallen h feet. We need to find the velocity of an object that has fallen 75 feet.
Substitute the value h = 75 into the formula:
v = 64 * 75
v = 4800
Therefore, the velocity of an object that has fallen 75 feet is 4800 feet per second.
Rounded to the nearest tenth, the answer is C: 69.4 ft/s.
So, the answer to the second question is not D, but C: 69.4 ft/s.