Suppose just go is selling magazine subscriptions each of the scription cost $20 the company pays the school half of the total sales in dollars the school must also pay a one time fee of $18 right and solve any Quetion to determine the fewest number of the scription that can be sold to earn a profit of $200
P = Income-Expense=20x-((20x/2)+18)=200.
20x - (10x+18) = 200.
20x - 10x - 18 = 200.
10x = 218.
X = 21.8 or 22 Copies.
To determine the fewest number of subscriptions that need to be sold to earn a profit of $200, we need to consider the costs and revenue involved.
Let's break down the information provided:
- Each subscription costs $20.
- The company pays the school half of the total sales in dollars.
- The school must pay a one-time fee of $18.
- The goal is to earn a profit of $200.
First, let's calculate the total cost incurred by the school:
One-time fee = $18
Next, let's calculate the revenue generated by selling magazine subscriptions:
Revenue per subscription = $20
Total revenue = Number of subscriptions × Revenue per subscription
The school receives half of the total sales, so the amount the school receives can be calculated as:
Amount received by the school = Total revenue ÷ 2
Now, let's calculate the total profit earned by the school:
Total profit = Amount received by the school - Total cost
We want the total profit to be $200, so we can set up the equation:
Total profit = $200
Equating the above equation with the profit equation, we have:
Amount received by the school - Total cost = $200
Now, we can substitute the values we know into the equation:
Total revenue ÷ 2 - $18 = $200
Simplifying the equation, we get:
Total revenue ÷ 2 = $200 + $18
Total revenue ÷ 2 = $218
Multiply both sides of the equation by 2 to isolate the total revenue:
Total revenue = $218 × 2
Total revenue = $436
Now, substituting the value of total revenue into the original revenue equation, we can find the number of subscriptions:
Number of subscriptions × $20 = $436
Dividing both sides of the equation by $20, we find:
Number of subscriptions = $436 ÷ $20
Number of subscriptions = 21.8
Since we cannot sell fractional subscriptions, we need to round up to the nearest whole number:
Number of subscriptions = 22
Therefore, to earn a profit of $200, the fewest number of subscriptions that need to be sold is 22.