What is the mass in amu of 3.12 moles of Ba(NO3)2?
To calculate the mass in amu (atomic mass units) of a given substance, you need to know the molar mass of that substance.
To find the molar mass of Ba(NO3)2 (barium nitrate), you can add up the atomic masses of all the atoms in the formula. The atomic masses can be found on the periodic table.
The atomic mass of Ba (barium) is 137.33 g/mol,
the atomic mass of N (nitrogen) is 14.01 g/mol,
and the atomic mass of O (oxygen) is 16.00 g/mol.
To get the molar mass of Ba(NO3)2, you need to multiply the atomic masses of each element by the number of atoms present in the formula, and then sum up these values:
Ba: 1 atom x 137.33 g/mol = 137.33 g/mol
N: 2 atoms x 14.01 g/mol = 28.02 g/mol
O: 6 atoms x 16.00 g/mol = 96.00 g/mol
Now, add up these values:
Molar mass of Ba(NO3)2 = 137.33 g/mol + 28.02 g/mol + 96.00 g/mol = 261.35 g/mol
Since you have 3.12 moles of Ba(NO3)2, you can multiply the molar mass by the number of moles to find the mass:
Mass = 3.12 moles x 261.35 g/mol = 815.71 g
So, the mass in amu of 3.12 moles of Ba(NO3)2 is 815.71 g.