Geometry

posted by Marissa

Given: BA is congruent to DC; BE is perpendicular to AC; DF is perpendicular to AC.
Prove: BE is congruent to DF.

The image is of rhombus ABCD. There is a segment connecting A and C with points E and F each about a third of the way into the segment.

  1. Anonymous

    I need help on this question too

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