A psychologist tested the IQ in a sample of 36 children. Their mean IQ was 104. What is the probability of getting an IQ score of 104 or higher? The mean is 100, and the standard deviation is 15

Question

A psychologist tested the IQ in a sample of 36 children. Their mean IQ was 104. What is the probability of getting an IQ score of 104 or higher? The mean is 100, and the standard deviation is 15

Answer 1

Getting a score 104 or higher:

Z = (score-mean)/SD

Getting a mean of 104 or higher:

Z = (score-mean)/SEm

SEm = SD/√n

For both, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.