Calculate K at 298 K for the following reactions.
NO(g) + 1/2 O2(g)......> NO2(g)
Nog 86.60
No2 g 51
o2.... O
I got 6.81 x 10^-7........thank you.
Well, it looks like you've done all the hard work already! But just to add some fun to your answer, I must say that calculating K can be quite an adventure. It's like going on a treasure hunt! So, let's dig into it together.
According to the equation, NO(g) + 1/2 O2(g) → NO2(g), we can write the expression for K as:
K = [NO2] / ([NO] * [O2]^0.5)
To find the value of K at 298 K, we need to use the provided concentrations: [NO] = 86.60, [NO2] = 51, and [O2] = 0 (unless there's a miracle and the oxygen concentration turns out to be something different from zero).
Plug in those values and see if your final answer matches mine. Remember, K is just a number, but the process of getting there is the real enjoyment. Happy calculations!
To calculate the equilibrium constant (K) at 298 K for the given reaction:
NO(g) + 1/2 O2(g) → NO2(g),
you need the concentrations of each species at equilibrium.
From the information provided, the initial concentration of NO(g) is given as 86.60, and the concentration of NO2(g) is given as 51. However, the concentration of O2(g) is not given.
Since the stoichiometric coefficient of O2(g) is 1/2 in the balanced equation, you need to determine the concentration of O2(g) at equilibrium. This can be done by using the stoichiometry and the given concentrations of NO(g) and NO2(g).
Let's assume x is the concentration of O2(g) at equilibrium.
According to the balanced equation, the molar ratio between NO(g), O2(g), and NO2(g) is 1:1/2:1.
Based on this ratio, the change in concentration of O2(g) can be expressed as:
Δ[O2] = -1/2 * Δ[NO2]
= -1/2 * (51 - 86.60)
= -1/2 * (-35.60)
= 17.80
Since the initial concentration of O2(g) was not given, assume it to be zero. Hence, the concentration at equilibrium is:
[O2] = 0 + 17.80
= 17.80
Now you have the equilibrium concentrations for all species:
[NO] = 86.60, [O2] = 17.80, and [NO2] = 51.
To calculate K at 298 K, use the following equation:
K = ([NO2] / ([NO] * [O2 ^(1/2)]))
Plugging in the values:
K = (51 / (86.60 * (17.80)^(1/2)))
Calculating this expression will give you the value of K at 298 K.
Based on the information you provided, the value you obtained for K is 6.81 x 10^-7.