How much time does it take for a car to come to rest if it has an initial speed of 22m/s and slows with a deceleration of 6.1 m/s^2
Will my answer be 3.6 m/s^2
No, that is not right. You are looking for time
vf=vi+at, and a is -6.1m/s^2, solve for time.
To determine the time it takes for a car to come to rest, you can use the kinematic equation:
v = u + at
where:
v = final velocity (0 m/s, since the car comes to rest)
u = initial velocity (22 m/s)
a = deceleration (-6.1 m/s^2, since it slows down)
t = time
Rearranging the equation, we have:
t = (v - u) / a
Substituting the given values, we get:
t = (0 - 22) / (-6.1)
Simplifying, we find:
t ≈ 3.61 seconds
So, it will take approximately 3.61 seconds for the car to come to rest.