Calculus
posted by Anonymous .
Evaluate using integration by parts, substitution, or both if necessary.
the intergral of cos 2x ln(sin 2x) dx
My work:
w= sin2x
dw= 2cos2xdx
1/2 dw= cos2xdx
1/2 integrsl sign ln(w)dw
u= lnw
u'= 1/w
v= w
v'=1
1/2 [(lnw)(w) integral sign (1/w)(w) dw]
1/2 (wlnww)
Final Answer:
1/2 sin2xln(sin2x)1/2 sin2x
This answer seems correct to me, but when I typed this in, the answer is said to be incorrect!
Please check my work and see if I made any mistakes.
Thank you!

Calculus 
Reiny
Wolfram said this:
http://www.wolframalpha.com/input/?i=integral+cos+2x+ln%28sin+2x%29+dx
look at the last version of the "alternate forms"
Respond to this Question
Similar Questions

Calculus II
Evaluate the integral using method of integration by parts: (integral sign)(e^(2x))sin(5x)dx 
Calculus
First make a substitution and then use integration by parts to evaluate. The integral of (x^9)(cos(x^5))dx What do you substitute first? 
Calc
First make an appropriate substitution and then use integration by parts to evaluate the indefinite integrals: ∫ sinx cos³x e^(1sin²x) dx I was going to substitute u= 1  sin²x, but then i got du = ½ sinxcosx  ½ xdx, so … 
calculus
evaluate the following indefinite integrals by substitution & check the result by differentiation. ∫(sin2x)^2 cos2xdx 
Calculus AP
Evaluate the integral interval from [0 to pi] t sin(3t)dt Use integration by parts u=t and dv=sin(3t)dt. then du=dt and v=cos(3t)/3 here is my problem but Im having problem to solve with pi. ∫t sin(3t)dt = tcos(3t)/3  ∫[cos(3t)/3]dt … 
Calculus AP
hi again im really need help TextBook: James Stewart:Essential Calculus, page 311. Here the problem #27: First make a substitution and then use integration by parts to evaluate the integral. Integral from sqrt(pi/2) TO sqrt(pi)of θ^3 … 
Integration by Parts
integral from 0 to 2pi of isin(t)e^(it)dt. I know my answer should be pi. **I pull i out because it is a constant. My work: let u=e^(it) du=ie^(it)dt dv=sin(t) v=cos(t) i integral sin(t)e^(it)dt= e^(it)cos(t)+i*integral cost(t)e^(it)dt … 
Calculus
Evaluate using Integration by Parts. x^2 cos(3x) dx 
Math
Show using integration by parts that: e^3x sin(2x)dx = 4/26 e^3x (3/2 sin(2x)  cos(2x)) +c Bit stuck on this. Using rule f udv = uv  f vdu u = e^3x dv + sin(2x)dx f dv = v du/dx = 3e^3x v = 1/2 cos(2x) so uv  f vdu: = (e^3x)(1/2 … 
Question on Integration
(i) Evaluate integral [ x^3 / (x^2 + 4)^2 ] using trigonometric substitution. (ii) Evaluate integral [ x^3 / (x^2 + 4)^2 ] using regular substitution. (iii) Use a right triangle to check that indeed both answers you obtained in parts …